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Coordinates

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  • Coordinates
  • Question 17
  • Answer

Question 17

Answer

D

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8/10
  • Question 19
  • Answer

Question 19

Answer

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9/10
  • Question 12
  • Answer

Question 12

Answer

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5/10
  • Question 13
  • Answer

Question 13

Answer

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5/10
  • Question 12
  • Answer

Question 12

Answer

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5/10
  • Question 6
  • Answer

Question 6

Answer

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4/10
  • Question 12
  • Answer

Question 12

Answer

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Difficulty Rating

7/10
  • Question 14
  • Answer

Question 14

Answer

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Difficulty Rating

6/10
  • Question 22
  • Answer

Question 22

Answer

Reflection is per the grid markings

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7/10
  • Question 19
  • Answer

Question 19

Answer

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4/10
  • Question 24
  • Answer

Question 24

 

Answer

D Coordinates are (1,0)

Area = 3 square units

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5/10
  • Question 24
  • Answer

Question 24

Answer

a-b) See below for plotted data

c) Coordinates of D are (1,-3)

d) Its a 4 by 4 square so 16 square units

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  • Question 13
  • Answer

Question 13

Answer

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  • Question 25
  • Answer

Question 25

Answer

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9/10
  • Question 17
  • Answer

Question 17

Answer

See below:

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4/10
  • Question 35
  • Answer

Question 35

Answer

a) See below

b) (2,7)

c) See above for drawing

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Difficulty Rating

7/10
  • Question 32
  • Answer

Question 32

Answer

a) Point W which is (9,1)

b) Point X which is (5,7)

c) Point Y which is (4,8)

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5/10
  • Question 29
  • Answer

Question 29

Answer

a) See below

b) A Trapezium

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4/10
  • Question 29
  • Answer

Question 29

Answer

a) See the diagram below

b) (5,4)

c) 17.5cm²

Area: Point A (1,5); B (4,9); C (8,8); D (5,4)

2 Triangles in effect with ABD & BCD.

ABD Area – A to midpoint BD is 3.5. Base is 5 for B to D (co-ordinate for Y axis for B of 9 less co-ordinate for D of 4)

So area of ABD = (1/2 * 3.5 * 5) =  15.75 * 2 = 8.75. * 2 as there are 2 triangles = 17.5

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8/10
  • Question 27
  • Answer

Question 27

Answer

a) (1,5)

b) (1,1) ; (3,1); (4,6)

isosceles ===== 2 equal angles

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5/10
  • Question 25
  • Answer

Question 25

Answer

a) (2,6)

Read horizontal axis always first when reading coordinates. Then Vertical axis

b) See below

c) i) (8,2)

A quarter of the distance from C to A would be from (8,0) to (8,8). Therefore, the difference in spaces is 8 on the vertical axis from C to A. 1/4 of this is 2 so the revised co-ordinates would be (8,2).

c)ii) (5,7)

A is (8,8) and B is (2,6). The difference between the coordinates is (-6,-2). Therefore, you move half of this from the point A which means you move by (-3,-1) from point A. This would give revised co-ordinates of (5,7) for the Silver. You apply addition and subtraction techniques in Coordinates

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4/10
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