**Reflection is per the grid markings**

**D Coordinates are (1,0)**

**Area = 3 square units**

**a-b) See below for plotted data**

**c) Coordinates of D are (1,-3)**

**d) Its a 4 by 4 square so 16 square units**

**See below:**

**a) See below**

**b) (2,7)**

**c) See above for drawing**

a) Point W which is **(9,1)**

b) Point X which is **(5,7)**

c) Point Y which is **(4,8)**

**a) See below**

**b) A Trapezium**

**a) See the diagram below**

**b) (5,4)**

**c) 17.5cm²**

Area: Point A (1,5); B (4,9); C (8,8); D (5,4)

2 Triangles in effect with ABD & BCD.

ABD Area – A to midpoint BD is 3.5. Base is 5 for B to D (co-ordinate for Y axis for B of 9 less co-ordinate for D of 4)

So area of ABD = (1/2 * 3.5 * 5) = 15.75 * 2 = 8.75. * 2 as there are 2 triangles = 17.5

**a) (1,5)**

**b) (1,1) ; (3,1); (4,6)**

isosceles ===== 2 equal angles

**a) (2,6)**

Read horizontal axis always first when reading coordinates. Then Vertical axis

**b) See below**

**c) i) (8,2)**

A quarter of the distance from C to A would be from (8,0) to (8,8). Therefore, the difference in spaces is 8 on the vertical axis from C to A. 1/4 of this is 2 so the revised co-ordinates would be (8,2).

**c)ii) (5,7)**

A is (8,8) and B is (2,6). The difference between the coordinates is (-6,-2). Therefore, you move half of this from the point A which means you move by (-3,-1) from point A. This would give revised co-ordinates of (5,7) for the Silver. You apply addition and subtraction techniques in Coordinates