a)i) 1/4 a)ii) 0.25 b) i) See below b) ii) 80% a) i) 31° W = 180 – 107 – 42 = 31 180° in a straight line a)ii) Reason is 180 in a straight line so its 180 less 107 less 42 to give the missing angle b) x = 52°; y= 47° For x…given JKL & MKN are straight lines, opposite angles in this set up are equal. Hence x = 52 For y….180 – 52 – 81 = 47° a) 0.03 b) 7 If 7.50 or above, then rounds to 8. Between 6.500 and 7.499, rounds to 7 c) 0.75 d) 0.07; 0.14; 0.306; 0.35; 0.4 e) 31/100 Remember 1.00 is 100% is 1/1. So 0.5 is 50% is 50/100. Work from there a) Cardiff b) -8C If temperature had fallen by 5C in London by midnight, temperature would now be -3-5 = -8 c) 3C 2 – -1 a) Equilateral Triangle b) Octagon c) a,c,d,e,h,i a) 40% 12 toffee = 60%. 8/20 are not toffees a) 2 Mode is the most common number b) 15 Range is highest – lowest c) 4 Mean = Average. Add up all of the numbers and divide by the number of instances 40/10 a) 8.23 b) 1 hour 35 mins 08:45 – 09:00 = 00:15 09:00 – 10:00 = 01:00 10:00 – 10:20 = 00:20 Total time is 0.15 + 1.00 + 0.2 = 1hour 35mins a) 20mins Use HCF & LCM. Work on the normal basis that 3 is 1/3 of 9. So if 9km = 1 hour, 3km = 1/3rd of 1 hour b) 2km 1/4 of the 8km/h = 15mins. So this is 2km 72cm (15 * 4) + (3*4) = 60 + 12
