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Maths-11-plus-Dulwich-Paper-A - 11 plus exams tutor. 11+ tutor Feltham. Eleven Plus Exams

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1.5

  1. 3 1/4 – 1 3/4 = 1 1/2
  2. As a decimal, this is 1.5

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3/10

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4/10

a) 12

1/4 * 48/1

b) 2

48 * 1/2 = 24.

24 * 1/3 = 8

8 * 1/4 = 2

Remember of in maths means multiply

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a) 1/8

45/360. Start off with 5 as the highest common denominator. Although there is a higher one

So 45/360 would become 9/72

Then 9/72 becomes 1/8

b) 40

Its the usual formula approach for this:

60/360 * 240/1

Then simplify each fraction (so 60/360 becomes 1/6)

Revised calculation is 1/6 * 240/1. Cross cancel and then multiply from there. See online videos on Youtube for 123tutors for further guidance

c) 450

Football is 135°. So 135/360 * 1200

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6/10

a) 7

Mode is the most common number. This is 7

b) 8

8+7+11+6+9+7 = 48

48/6

c) 5

Range is highest minus lowest

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85p

  1. 12 * 65p = £7.80
  2. £7.80 – £6.95 = 85p

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1/20; 1/5; 1/4; 6/20; 3/2

  1. Use estimation if needed. So this would involve converting all of the fractions to the highest denominator which is 20
  2. 6/20; 4/20; 30/20; 1/20; 5/20
  3. This makes it easier to rank them

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a) Rhys 30 miles. Sarah 60 miles

Work on ratios. Rhys 10:20 Sarah

This is 30 parts. So into 90, Rhys gets 30 and Sarah 60

b) 2 hours

Given they are travelling towards each other

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a) 1200mm²

Area of rectangle = LxW = 60mm x 20mm

b) 40 triangles

2 Triangles will joined together have dimensions of LxW = 12mmx5mm. So they form a rectangle

Therefore, in 60mm across, you get 5 “blocks” of 2 triangles. And you can go to a height of 4 blocks

So in total 5 * 4 blocks = 20 blocks. 2 triangles per block so 40 triangles

c) 1200mm

Perimeter of 1 triangle = 12+5+13=30mm

Total number of triangles = 40

Total Perimeter =1200mm

d) 1.2m

10mm = 1cm

100cm = 1m

1000mm = 1m

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a) 4 plates

BB1, BB2, BB3, BB4

b) 16

Per above * 4 since you have AA1-4,BB1-4,CC1-4,DD1-4

c) 12

AB1,AB3,AC1,AC3,AD1,AD3,BA1,BA3,CA1,CA3,DA1,DA3

d) 3/8

Alphabetical order: AB,AC,AD,BC,BD,CD. Each one has 4 possible plates. So AB1,AB2,AB3,AB4,AC1,AC2 etc

Total number of possible plates = 24

24/64 = 3/8

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12

  1. Can use algebra to solve.
  2. 2(x-4) = x+4
  3. 2x-8=x+4
  4. Rearrange
  5. x=12

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9/10

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1/4

4 parts of 16 shaded = 4/16 = 1/4

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6/10